8v^2+2=-8v

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Solution for 8v^2+2=-8v equation: 



8v^2+2=-8v

We move all terms to the left:

8v^2+2-(-8v)=0

We get rid of parentheses

8v^2+8v+2=0

a = 8; b = 8; c = +2;
Δ = b2-4ac
Δ = 82-4·8·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-8}{16}=-1/2$

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